Get month and year from a datetime in SQL Server 2005

I need the month+year from the datetime in SQL Server like 'Jan 2008'. I'm grouping the query by month, year. I've searched and found functions like datepart, convert, etc., but none of them seem useful for this. Am I missing something here? Is there a function for this?

select 
datepart(month,getdate()) -- integer (1,2,3...)
,datepart(year,getdate()) -- integer
,datename(month,getdate()) -- string ('September',...)

Beginning with SQL Server 2012, you can use:

SELECT FORMAT(@date, 'yyyyMM')

Use:

select datepart(mm,getdate())  --to get month value
select datename(mm,getdate())  --to get name of month

Funny, I was just playing around writing this same query out in SQL Server and then LINQ.

SELECT 
    DATENAME(mm, article.Created) AS Month, 
    DATENAME(yyyy, article.Created) AS Year, 
    COUNT(*) AS Total 
FROM Articles AS article 
GROUP BY 
    DATENAME(mm, article.Created), 
    DATENAME(yyyy, article.Created) 
ORDER BY Month, Year DESC

It produces the following ouput (example).

Month | Year | Total

January | 2009 | 2

In SQL server 2012, below can be used

select FORMAT(getdate(), 'MMM yyyy')

This gives exact "Jun 2016"

How about this?

Select DateName( Month, getDate() ) + ' ' + DateName( Year, getDate() )

That format doesn't exist. You need to do a combination of two things,

select convert(varchar(4),getdate(),100)  + convert(varchar(4),year(getdate()))

( Month(Created) + ',' + Year(Created) ) AS Date

the best way to do that is with :

dateadd(month,datediff(month,0,*your_date*),0)

it will keep your datetime type

returns the full month name, -, full year e.g. March-2017

CONCAT(DATENAME(mm, GetDate()), '-', DATEPART(yy, GetDate()))

The question is about SQL Server 2005, many of the answers here are for later version SQL Server.

select convert (varchar(7), getdate(),20)
--Typical output 2015-04

SQL Server 2005 does not have date function which was introduced in SQL Server 2008

---Lalmuni Demos---
create table Users
(
userid int,date_of_birth date
)
---insert values---
insert into Users values(4,'9/10/1991')

select DATEDIFF(year,date_of_birth, getdate()) - (CASE WHEN (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()),date_of_birth)) > getdate() THEN 1 ELSE 0 END) as Years, 
MONTH(getdate() - (DATEADD(year, DATEDIFF(year, date_of_birth, getdate()), date_of_birth))) - 1 as Months, 
DAY(getdate() - (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()), date_of_birth))) - 1 as Days,
from users

Converting the date to the first of the month allows you to Group By and Order By a single attribute, and it's faster in my experience.

declare @mytable table(mydate datetime)
declare @date datetime
set @date = '19000101'
while @date < getdate() begin
    insert into @mytable values(@date)
    set @date = dateadd(day,1,@date)
end

select count(*) total_records from @mytable

select dateadd(month,datediff(month,0,mydate),0) first_of_the_month, count(*) cnt
from @mytable
group by dateadd(month,datediff(month,0,mydate),0)

cast(cast(sq.QuotaDate as date) as varchar(7))

gives "2006-04" format

I had the same problem and after looking around I found this:

SELECT DATENAME(yyyy, date) AS year
FROM Income
GROUP BY DATENAME(yyyy, date)

It's working great!

It's work great.

DECLARE @pYear VARCHAR(4)

DECLARE @pMonth VARCHAR(2)

DECLARE @pDay VARCHAR(2)

SET @pYear  = RIGHT(CONVERT(CHAR(10), GETDATE(), 101), 4)

SET @pMonth = LEFT(CONVERT(CHAR(10), GETDATE(), 101), 2)

SET @pDay   = SUBSTRING(CONVERT(CHAR(10), GETDATE(), 101), 4,2)

SELECT @pYear,@pMonth,@pDay

  ,datename(month,(od.SHIP_DATE)) as MONTH_

Answer: MONTH_ January January September October December October September

Yes, you can use datename(month,intime) to get the month in text.

The following works perfectly! I just used it, try it out.

date_format(date,'%Y-%c')